Problem Link:Reverse and Add
NB:There is trick to solve this problem thus read the problem carefully.You may get compile error in C for input format.So implement the program in .cpp extension.
Source code in C++:
#include<stdio.h>
#define lli long long int
#define file freopen("in.txt","rt",stdin)
int main()
{
// file;
lli num,revnum,sum1,sum2,d,r,cnt,num1;
int test;
while(scanf("%d",&test)!=EOF)
{
while(test--)
{
cnt=0;
scanf("%lld",&num);
do
{
num1 = num;
sum1=0;
while(num>0)
{
r = num%10;
num = num/10;
sum1 = sum1*10+r;
}
num=num1+sum1;
sum2=0;
while(num>0)
{
r = num%10;
num = num/10;
sum2 = sum2*10+r;
}
cnt++;
num=sum1+num1;
}
while((num1+sum1)!=sum2);
printf("%lld %lld\n",cnt,sum2);
}
}
return 0;
}
NB:There is trick to solve this problem thus read the problem carefully.You may get compile error in C for input format.So implement the program in .cpp extension.
Source code in C++:
#include<stdio.h>
#define lli long long int
#define file freopen("in.txt","rt",stdin)
int main()
{
// file;
lli num,revnum,sum1,sum2,d,r,cnt,num1;
int test;
while(scanf("%d",&test)!=EOF)
{
while(test--)
{
cnt=0;
scanf("%lld",&num);
do
{
num1 = num;
sum1=0;
while(num>0)
{
r = num%10;
num = num/10;
sum1 = sum1*10+r;
}
num=num1+sum1;
sum2=0;
while(num>0)
{
r = num%10;
num = num/10;
sum2 = sum2*10+r;
}
cnt++;
num=sum1+num1;
}
while((num1+sum1)!=sum2);
printf("%lld %lld\n",cnt,sum2);
}
}
return 0;
}
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